Which of the following represents the correct order of non-metallic character among boron (B), carbon (C), nitrogen (N), fluorine (F) and silicon (Si)?
1. B > C > Si > N > F
2. Si > C > B > N > F
3. F > N > C > B > Si
4. F > N > C > Si > B
Step 1: Periodic trends
Across a period, effective nuclear charge generally increases, resulting in a greater tendency to attract electrons.
Down a group, atomic size and shielding increase, generally reducing non-metallic character.
Step 2: Compare the given elements
Fluorine (F): Has the highest non-metallic character among the given elements.
Nitrogen (N): Is less non-metallic than fluorine but more non-metallic than carbon.
Carbon (C): Has greater non-metallic character than boron.
Boron (B): Is more non-metallic than silicon according to the usual periodic trend.
Silicon (Si): Has the lowest non-metallic character among these elements.
Step 3: Arrange in decreasing order
F > N > C > B > Si
Therefore, Option 3 represents the correct decreasing order of non-metallic character.
Final Answer: Option 3 — F > N > C > B > Si
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