When a current of \(5~\text{mA}\) is passed through a galvanometer having a coil of resistance \(15~\Omega\), it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range \(0\text{-}10~\text{V}\) is:
1. \( 1.985 \times 10^3 ~\Omega \)
2. \( 2.045 \times 10^3 ~\Omega \)
3. \( 2.535 \times 10^3 ~\Omega \)
4. \( 4.005 \times 10^3 ~\Omega\)

Subtopic:  Conversion to Ammeter & Voltmeter |
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The resistance of a galvanometer is \(50~\Omega\) and the maximum current which can be passed through it is \(0.002~\text{A}\). What resistance must be connected to it in order to convert it into an ammeter of range \((0\text-0.5~\text{A})?\)
1. \(0.2~\Omega\)
2. \(0.002~\Omega\)
3. \(0.02~\Omega\)
4. \(0.5~\Omega\)

Subtopic:  Conversion to Ammeter & Voltmeter |
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\( 72 ~\Omega\) galvanometer is shunted by a resistance of \(8 ~\Omega.\) The percentage of the total current that passes through the galvanometer is:
1. \(0.1\%\)
2. \(10\%\)
3. \(25\%\)
4. \(0.25\%\)
Subtopic:  Conversion to Ammeter & Voltmeter |
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Circuit I is converted to voltmeter after adding resistance R and current in circuit I is 1 mA. Circuit II is converted to ammeter after adding resistance r as shown. If current through battery in circuit II is 10 mA and current through galvanometer is 1 mA, then find R and r if resistance of galvanometer is 54 Ω.



1. R = 49946 Ω, r = 54 Ω
2. R = 6 Ω, r = 49946 Ω
3. R = 49946 Ω, r = 49946 Ω
4. R = 49946 Ω, r = 6 Ω

 
Subtopic:  Conversion to Ammeter & Voltmeter |
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