A particle of mass \(m\) is thrown upwards from the surface of the earth, with a velocity \(u.\) The mass and the radius of the earth are, respectively, \(M\) and \(R.\) \(G\) is the gravitational constant and \(g\) is the acceleration due to gravity on the surface of the earth. The minimum value of \(u\) so that the particle does not return back to earth is:

1. \(\sqrt{\dfrac{2 {GM}}{{R}^2}} \)

2. \(\sqrt{\dfrac{2 {GM}}{{R}}} \)

3.\(\sqrt{\dfrac{2 {gM}}{{R}^2}} \)

4. \(\sqrt{ {2gR^2}}\)

Subtopic:  Escape velocity |
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AIPMT - 2011
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For a satellite, the escape velocity is \(11.2\) km/s from the surface of the earth. If the satellite is launched at an angle of \(60^\circ\) with the vertical, then the escape velocity will be:
1. \(11.2 ~\cos60^\circ\) km/s 2. \(11.2 ~\sin60^\circ\) km/s
3. \(11.2\) km/s 4. \(11.2 ~\tan60^\circ\) km/s
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If the radius of a planet is \(R\) and its density is \(\rho, \) the escape velocity from its surface will be

1. \(V_{e} \propto p R\)                         

2. \(V_{e} \propto R \sqrt{\rho}\)

3. \(V_{e} \propto \dfrac{\sqrt{p}}{R}\)                        

4. \(V_{e} \propto \dfrac{1}{\sqrt{p} R}\)

 

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If the escape velocity from the surface of Earth is denoted by \(v,\) then what would be the escape velocity from the surface of a planet whose mass is \(9\) times and radius is \(16\) times that of Earth?
1. \(\dfrac{v}{3}\) 2. \(\dfrac{2v}{3}\)
3. \(\dfrac{3v}{4}\) 4. \(\dfrac{9v}{4}\)
Subtopic:  Escape velocity |
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NEET - 2024
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If mass of a planet is \(9\) times that of the earth and radius is \(2\) times that of the earth, then the escape speed from this planet is:
(\(v_{e}\)is escape speed from the Earth.)
1. \(\dfrac{v_e}{\sqrt2}\)

2. \(\dfrac{v_e}{2\sqrt2}\)

3. \(\dfrac{3v_e}{\sqrt2}\)

4. \(\dfrac{v_e}{2}\)
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A body is moving in a low circular orbit about a planet of mass \(M\) and radius \(R. \) The radius of the orbit can be taken to be \(R\) itself. The ratio of the speed of this body in the orbit to the escape velocity from the planet is:

1. \(\sqrt{2}\)

2. \(\dfrac{1}{\sqrt{2}}\)

3. \(2\)

4. \(1\)

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A satellite is moving around earth surface. How much minimum speed should be increased so that it escapes from earth surface? (\(g\) = acceleration due to gravity, \(R\) = radius of earth)

1. \(2\sqrt{gR} \)

2. \(\left({\sqrt{2}-1}\right)\sqrt{gR} \)

3. \(\dfrac{gR}{2}\)

4. \(\left({\sqrt{3}-1}\right)\sqrt{gR}\)
Subtopic:  Escape velocity |
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The escape velocity of a rocket launched from the surface of the earth towards a planet:
1. does not depend on the mass of the rocket.
2. does not depend on the mass of the earth.
3. depends on the mass of the rocket.
4. depends on the mass of the planet towards which it is moving.
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A planet has a radius twice but density \(\dfrac14\) as compared to earth. The ratio of escape velocity from earth to that from the planet will be:
1. \(1:2\) 2. \(1:1\)
3. \(2:1\) 4. \(3:1\)
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The escape velocity of a particle, projected tangentially from the surface of a planet of radius \(R,\) is: (\(g\) is the gravitational acceleration on the planet's surface)
1. \(\sqrt{5gR}\)       2. \(\sqrt{3gR}\)      
3. \(\sqrt{2gR}\) 4. infinite
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