The electric potential as a function of \(x,~y\) is given by \(V = 5(x^{2}-y^{2})~\text{V}.\) The electric field at a point \((2,3)~\text{m}\) is: (in \(\text{V/m}\))
1. \((-20 \hat{\imath}+30 \hat{\jmath})\)
2. \((20 \hat{\imath}-30 \hat{\jmath}) \)
3. \((20 \hat{\imath}+45 \hat{\jmath}) \)
4. \((-4 \hat{\imath}+6 \hat{\jmath})\)
Subtopic:  Relation between Field & Potential |
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Potential energy \((V)\) versus distance \((x)~\) is given by the graph. Rank various regions as per the magnitudes of the force \((F)\) acting on a particle from high to low.
                        
1. \({F}_{\mathrm{BC}}>{F}_{\mathrm{CD}}>{F}_{\mathrm{DE}}>{F}_{\mathrm{AB}}\)
2. \({F}_{\mathrm{CD}}>{F}_{\mathrm{AB}}>{F}_{\mathrm{BC}}>{F}_{\mathrm{DE}}\)
3. \({F}_{\mathrm{CD}}>{F}_{\mathrm{DE}}>{F}_{\mathrm{AB}}>{F}_{\mathrm{BC}}\)
4. \({F}_{\mathrm{BC}}>{F}_{\mathrm{AB}}>{F}_{\mathrm{DE}}>{F}_{\mathrm{CD}}~\)
Subtopic:  Relation between Field & Potential |
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The electric field in a region is given by \(\vec{E}=A x \hat{i}+B y \hat{j},\) where \(A =10~\text{V/m}{^2}\) and \(B =5~\text{V/m}{^2}.\) If the electric potential at a point \((10, 20)\) is \(500~\text{V}\), then the electric potential at origin is:
1. \(1000\) V
2. \(500\) V
3. \(2000\) V
4. \(0\) V
Subtopic:  Relation between Field & Potential |
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Two large plane parallel conducting plates are kept \(10 ~\text{cm}\) apart as shown in figure. The potential difference between them is \({V}.\) The potential difference between the points \(A\) and \(B\) (shown in the figure) is:
                                          
1. \(3/4~\text{V}~\)
2. \(1~\text{V}~\)
3. \(2/5~\text{V} ~\)
4. \(1/4~\text{V} ~\)
Subtopic:  Relation between Field & Potential |
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For a charged spherical ball, electrostatic potential inside the ball varies with \({r}\) as \({V}=2{ar}^2+{b},\) here, \(a\) and \(b\) are constant and \(r\) is the distance from the center. The volume charge density inside the ball is:
\((\varepsilon=\) permittivity of the medium\()\)
1. \(-6a\epsilon_0\)
2. \(-12a\epsilon_0\)
3. \(-18a\epsilon_0\)
4. \(-3a\epsilon_0\)
Subtopic:  Relation between Field & Potential |
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The electric potential at any point \((x,y,z)~\text m\) in space is given by \(V=3x^{2}~\text V.\) The electric field at the point \((1,0,3)~\text m\) will be: 
1. \(3~\text{V/m},\) directed along the positive \(x\text-\)axis 
2. \(3~\text{V/m},\) directed along the negative \(x\text-\)axis 
3. \(6~\text{V/m},\) directed along the positive \(x\text-\)axis 
4. \(6~\text{V/m},\) directed along the negative \(x\text-\)axis 
Subtopic:  Relation between Field & Potential |
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Consider two charged metallic spheres \(S_1\) and \(​​S_2\) of radii& \(R_1\) and \(R_2,\) respectively. The electric fields \(E_1~(\text{on}~S_1)\) and \(E_2~(\text{on}~S_2)\) on their surfaces are such that \(E_1/E_2 = R_1/R_2.\) Then the ratio of \(V_1 (~\text{on} ~S_1)/V_2(~\text{on}~S_2)\) of the electrostatic potential on each sphere is:
1. \(\left(\dfrac{R_1}{R_2}\right) ^2 \) 2. \( \left(\dfrac{R_1}{R_2}\right)^3 \)
3. \( \left(\dfrac{R_2}{R_1}\right) \) 4. \( \left(\dfrac{R_1}{R_2}\right)\)
Subtopic:  Relation between Field & Potential |
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Concentric metallic hollow spheres radii \(R\) and \(4R\) hold charges \(Q_1\) and \(Q_2\) respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference \(V(R)-V(4R )\) is:
1. \( \frac{3 Q_1}{16 \pi \varepsilon_0 R} \)
2. \( \frac{3 Q_1}{4 \pi \varepsilon_0 R} \)
3. \( \frac{Q_2}{4 \pi \varepsilon_0 R} \)
4. \( \frac{3 Q_2}{4 \pi \varepsilon_0 R}\)

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A positive point charge is released from rest at a distance \(r_0\)​ from an infinitely long straight line of positive charge having uniform linear charge density. As the point charge moves directly away from (or toward — depending on sign) the line charge under electrostatic force, its speed \(v\) depends on its instantaneous distance \(r\) from the line charge.

              
The speed \(v\) as a function of \(r,\) is proportional to:
1. \( v \propto e^{+r / r_0} \)
2. \(v \propto \ln \left(\dfrac{r}{r_0}\right ) \)
3. \( v \propto\left(\dfrac{r}{r_0}\right) \)
4. \( v \propto \sqrt{\ln \left(\dfrac{r}{r_0}\right)} \)

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The electric field in a region is given by \(\vec{E}=(A x+B) \hat{i}\), where \(E\) is in \(\text{NC}^{-1}\) and \(x\) is in meters. The value of constants are \(A=20\) SI unit and \(B=10\) SI unit. If the potential at \(x=1\) is \(V_1\) and that at \(x=-5\) is \(V_2\), then \(V_1-V_2\) is:
1. \(-520~\text{V}\)
2. \(180~\text{V}\)
3. \(-48~\text{V}\)
4. \(320~\text{V}\)

Subtopic:  Relation between Field & Potential |
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