| 1. | Air |
| 2. | Liquid |
| 3. | Both have the same viscosity |
| 4. | None of these |
| 1. | As temperature increases, the viscosity of a liquid decreases. |
| 2. | As temperature increases, the viscosity of gas increases. |
| 3. | As temperature decreases, the viscosity of gas increases. |
| 4. | Both (1) and (2) |
If the terminal speed of a sphere of gold (density = \(19.5~\text{kg/m}^3\)) is \(0.2~\text{m/s}\) in a viscous liquid (density = \(1.5~\text{kg/m}^3\)), the terminal speed of a sphere of silver (density = \(10.5~\text{kg/m}^3\)) of the same size in the same liquid will be:
1. \(0.4~\text{m/s}\)
2. \(0.133~\text{m/s}\)
3. \(0.1~\text{m/s}\)
4. \(0.2~\text{m/s}\)
A spherical solid ball of volume \(V\) is made of a material of density \(\rho_1.\) It is falling through a liquid of density \(\rho_2(\rho_2<\rho_1)\) Assuming that the liquid applies a viscous force on the ball that is proportional to the square of its speed \(v,\) i.e., \(F_{\text{viscous}}=-kv^2(k>0),\) the terminal speed of the ball is:
| 1. | \( \dfrac{{Vg} \rho_1}{k} \) | 2. | \( \sqrt{\dfrac{{Vg} \rho_1}{k}} \) |
| 3. | \( \dfrac{{Vg}\left(\rho_1-\rho_2\right)}{k} \) | 4. | \( \sqrt{\dfrac{{Vg}\left(\rho_1-\rho_2\right)}{k}} \) |
| 1. | \(35\times 10^{-3}~\text{m/s}\) | 2. | \(25\times 10^{-3}~\text{m/s}\) |
| 3. | \(45\times 10^{-3}~\text{m/s}\) | 4. | \(15\times 10^{-3}~\text{m/s}\) |