What type of mechanism governs the chlorination reaction of methane?
1. Elimination
2. Substitution nucleophilic unimolecular (\(S_{N^1}\))
3. Free Radical
4. Substitution nucleophilic bimolecular ( \(S_{N^2}\))
The number of structural isomers of (with one double bond) and (with one triple bond) is:
1. \(\mathrm{C}_4 \mathrm{H}_8=3 ; \mathrm{C}_5 \mathrm{H}_8=3 \)
2. \(\mathrm{C}_4 \mathrm{H}_8=4 ; \mathrm{C}_5 \mathrm{H}_8=4 \)
3. \(\mathrm{C}_4 \mathrm{H}_8=3 ; \mathrm{C}_5 \mathrm{H}_8=4\)
4. \(\mathrm{C}_4 \mathrm{H}_8=4 ; \mathrm{C}_5 \mathrm{H}_8=3\)
The products formed after ozonolysis of Pent-2-ene are:
| 1. | Ethanal and Methanal | 2. | Ethanal and Propanal |
| 3. | Ethanal and Butanal | 4. | Ethanal and Ethanol |
An alkene ‘A’ on ozonolysis gives a mixture of ethanal and pentan-3-one.
The IUPAC name of ‘A’ is :
1. 3-Ethylpent-2-ene
2. 3-Ethylpent-2- yne
3. 2-Ethylpent-3-ene
4. 3-Ethylpent-4-yne
An alkene ‘A’ contains 3 C – Cσ bonds, 8 C – H σ bonds, and 1 C – C π bond,
‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. The IUPAC name of ‘A’ is:
| 1. | Prop-2-yne | 2. | But-2-ene |
| 3. | But-2-yne | 4. | Prop-2-ene |
Propanal and pentane-3-one are the products of ozonolysis of an alkene. The structural formula of the alkene is :
| 1. | 2. | ||
| 3. | 4. |
Which of the following is the correct balanced chemical equation for the combustion of butane?
| 1. | \(\mathrm{2 {C}_4 {H}_{10({g})}+13 {O}_{2({g})} \rightarrow 8 {CO}_{2({g})}+10 {H}_2 {O}} + Heat \) |
| 2. | \(\mathrm{2 {C}_4 {H}_{10({g})}+13 {O}_{2({g})} \rightarrow 9 {CO}_{2({g})}+10 {H}_2 {O}+} Heat \) |
| 3. | \(\mathrm{2 {C}_4 {H}_{10({g})}+14 {O}_{2({g})} \rightarrow 8 {CO}_{({g})}+10 {H}_2 {O}}+ Heat \) |
| 4. | \( \mathrm{{C}_4 {H}_{10({g})}+13 {O}_{2({g})} \rightarrow 8 {CO}_{({g})}+10 {H}_2 {O}}+ Heat\) |
Which isomer of pent-2-ene will have a higher boiling point and why?
1. Cis - less polar than trans
2. Trans - more polar than cis
3. Cis - more intermolecular forces
4. Trans - more dipole-dipole interactions
Benzene is extraordinarily stable, though it contains three double bonds, because of :
1. Delocalized protons
2. Delocalized neutrons
3. Resonance
4. None of the above.
Incorrect statement regarding aromaticity among the following is:
| 1. | The compound should have a planar structure. |
| 2. | The π–electrons of the compound are completely delocalized in the ring. |
| 3. | The total number of π–electrons present in the ring should be equal to (4n + 2) π electrons, where n = 0, 1, 2 … etc. This is known as Huckel’s rule. |
| 4. | The compound should have a linear structure. |