| Column-I (Term) | Column-II (Conditions) | ||
| (A) | Solute (s) ⇌ Solute (solution) | (I) | ∆G>0, K<1 |
| (B) | Spontaneous reaction | (II) | Saturated solution |
| (C) | Non-spontaneous reaction | (III) | ∆G<0, K>1 |
| (D) | Liquid ⇌ Vapour | (IV) | Boiling point |
Codes:
| A | B | C | D | |
| 1. | II | III | I | IV |
| 2. | IV | II | III | I |
| 3. | I | IV | III | II |
| 4. | II | IV | I | III |
Match the following equilibria with the corresponding condition.
| Column-I (Process) | Column-II (Corresponding term) |
||
| A. | Liquid ⇌ Vapour | I. | Saturated solution |
| B. | Solid ⇌ Liquid | II. | Boiling point |
| C. | Solid ⇌ Vapour | III. | Sublimation point |
| D. | Solute (s) ⇌ Solute (solution) | IV. | Melting point |
| V. | Unsaturated solution |
Codes:
| A | B | C | D | |
| 1. | II | IV | III | I |
| 2. | III | I | IV | II |
| 3. | V | IV | III | II |
| 4. | IV | V | III | II |
Given that the equilibrium constant (KC) at 800 K for the reaction N2(𝑔)+3H2(𝑔)⇋2NH3(𝑔) is 64. What is the equilibrium constant KC at the same temperature for the reaction NH3(g) ⇌ 1/2N2(g) + 3/2H2(g)?
| 1. | \(\dfrac{1}{4}\) | 2. | \(\dfrac{1}{8}\) |
| 3. | 8 | 4. | \(\dfrac{1}{64}\) |
| Assertion (A): | \(Ni(s)+4CO(g)\rightleftharpoons Ni(CO)_4(g)\\ \text{For the above reaction,}\\ K_C=\frac{[Ni(CO)_4]}{[CO]^4}\) |
| Reason (R): | For heterogeneous equilibrium, the concentrations of pure solids or liquids are not considered in the expression of the equilibrium constant. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
For the reaction equilibrium, \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \rightleftharpoons 2 \mathrm{NO}_2(g) \), the concentrations of N2O4 and NO2 at equilibrium are 4.8 \(\times\) 10-2 and 1.2 \(\times\) 10-2 mol L-1 respectively. The value of Kc for the reaction is:
1. 3.3 \(\times\) 102 mol L-1
2. 3 \(\times\) 10-1 mol L-1
3. 3 \(\times\) 10-3 mol L-1
4. 3 \(\times\) 103 mol L-1
The equilibrium constant for the reaction, N2(g) + O2(g) ⇌ 2NO(g) is
4 × 10–4 at 2000 K. In the presence of a catalyst,
the equilibrium is attained ten times faster.
Therefore, the equilibrium constant, in the presence of the catalyst,
at 2000 K is:
1. 40 × 10−4
2. 4 × 10−4
3. 4 × 10−3
4. Difficult to calculate and need more data
| (i) | \(\mathrm{{CO}(g)+{H}_{2} O(g) \rightleftharpoons {CO}_{2}(g)+{H}_{2}(g) ; K_{1}}\) |
| (ii) | \(\mathrm{CH}_{4}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g); K_{2}}\) |
| (iii) | \(\mathrm{CH}_{4}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}_{2}(\mathrm{g})+4 \mathrm{H}_{2}(\mathrm{g) ; K_{3}}\) |