A point mass is moving with a velocity \(v\) in the positive \({x\text-}\)direction. The velocity \(v\) (in m/s) is described by the equation \(v=5t+10t^2,\) where \(t\) is in seconds. The acceleration of the point mass at \(t=2\) s is:
1. zero 2. \(10~\text{m/s}^2\)
3. \(12~\text{m/s}^2\) 4. \(45~\text{m/s}^2\)
Subtopic:  Non Uniform Acceleration |
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Level 1: 80%+
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Two cars are moving towards each other, each with a speed of \(20\text{ m/s}.\) When they are \(300\text{ m}\) apart, both drivers apply the brakes simultaneously, causing each car to decelerate uniformly at \(2\text{ m/s}^2.\) What will be the distance between the two cars after both have come to rest?
1. \(200\text{ m}\)
2. \(50\text{ m}\)
3. \(100\text{ m}\)
4. \(25\text{ m}\)
Subtopic:  Non Uniform Acceleration |
 77%
Level 2: 60%+
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The position of a particle with respect to time \(t\) along the \({x}\)-axis is given by \(x=9t^{2}-t^{3}\) where \(x\) is in metres and \(t\) in seconds. What will be the position of this particle when it achieves maximum speed along the \(+{x} \text-\text{direction}?\)
1. \(32~\text m\)
2. \(54~\text m\)
3. \(81~\text m\)
4. \(24~\text m\)

Subtopic:  Non Uniform Acceleration |
 78%
Level 2: 60%+
AIPMT - 2007
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