The major product P formed in the following reaction sequence is:
1. 2.
3. 4.
Subtopic:  Alkanes, Alkenes and Alkynes - Chemical Properties |
 67%
Level 2: 60%+
NEET - 2024
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Match List-I with List-II:
List-I
(Reactions)
List-II
(Products)
A. I. \(\small\mathrm{{\left({CH}_3\right)_2 {C}={O}+{CO}_2+\mathrm{H}_2 {O} }}\)
B. II.
C. III.
D. IV. \(\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{OH} \)

Choose the correct answer from the options given below:
1. A-II, B-IV, C-III, D-I
2. A-II, B-III, C-IV, D-I
3. A-II, B-III, C-I, D-IV
4. A-IV, B-I, C-III, D-II
Subtopic:  Alkanes, Alkenes and Alkynes - Chemical Properties |
 72%
Level 2: 60%+
NEET - 2024
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For the given reaction:

'P' is:
1. 2.
3. 4.
Subtopic:  Alkanes, Alkenes and Alkynes - Chemical Properties |
Level 3: 35%-60%
NEET - 2024
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Determine the IUPAC name of the compound with the molecular formula C₆H₁₄ that contains two tertiary carbon atoms.
1. 2-Methyl pentane
2. 2, 3-Dimethylbutane
3. 2, 2-Dimethylbutane
4. n-Hexane

Subtopic:  Aliphatic Hydrocarbon -Nomenclature, Isomerism & Mechanism |
 72%
Level 2: 60%+
NEET - 2024
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Given below are two statements :
Statement I: The boiling point of three isomeric pentanes follows the order, 
\(\small\text { n-Pentane }>\text { Isopentane }>\text { Neopentane }\)
Statement II: When branching increases, the molecule attains the shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.

1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect but Statement II is correct.
4. Both Statement I and Statement II are correct.
Subtopic:  Aliphatic Hydrocarbon- Physical Properties |
 76%
Level 2: 60%+
NEET - 2024
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Among the following, the compound which contains the fewest tertiary carbons is:  
1. \((CH_3)_3C(CH_2)_2CH_3~~~~~~~~~~~~~\)
2. 4-isobutyl heptane
3.
4.
Subtopic:  Aliphatic Hydrocarbon- Physical Properties |
Level 3: 35%-60%
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The electron pair in the \(\pi -\) bond of an alkene has: 
 
1. 33% p character and are at a lower energy level than the electron pair in the \(\sigma -\) bond. 
2. 50% p character and are at a higher energy level than the electron pair in the  \(\sigma -\) bond. 
3. 100% p character and are at a lower energy level than the electron pair in the  \(\sigma -\) bond. 
4. 100% p character and are at a higher energy level than the electron pair in the  \(\sigma -\) bond.
Subtopic:  Aliphatic Hydrocarbon -Nomenclature, Isomerism & Mechanism |
Level 4: Below 35%
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The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is:

1.  The eclipsed conformation of ethane is more stable than staggered conformation because eclipsed conformation has no torsional strain.
2. The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has a torsional strain.
3. The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain.
4. The staggered conformation of ethane is less stable than eclipsed conformation because staggered conformation has a torsional strain.

Subtopic:  Aliphatic Hydrocarbon -Nomenclature, Isomerism & Mechanism |
 83%
Level 1: 80%+
NEET - 2016
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An unsaturated hydrocarbon 'A' reacts with two molecules of H2 and upon reductive ozonolysis A gives butane-1,4-dial, ethanal, and propanone.

The IUPAC name of A is:

1. 2-Methylocta-2,6-diene

2. 2-Methylocta-1,5-diene

3. 3-Methylocta-2,6-diene

4. 2-Methylocta-1,6-diene

Subtopic:  Aliphatic Hydrocarbon -Nomenclature, Isomerism & Mechanism |
 74%
Level 2: 60%+
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The most suitable reagent for the following conversion is:

1. Hg2+/ H+, H2O 2. Na/liquid NH3
3. H2, Pd/C, quinoline 4. Zn/HCl
Subtopic:  Aliphatic Hydrocarbon -Nomenclature, Isomerism & Mechanism |
 81%
Level 1: 80%+
NEET - 2019
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